How much zeros has the number $1000!$ at the end?
May 13, 2014 · 1 If a number ends with n n zeros than it is divisible by 10n 10 n, that is 2n5n 2 n 5 n. A factorial clearly has more 2 2 s than 5 5 s in its factorization so you only need to count …
Creating arithmetic expression equal to 1000 using exactly eight …
I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses. Here are the seven solutions I've found (on the Internet)...
probability - 1/1000 chance of a reaction. If you do the action …
A hypothetical example: You have a 1/1000 chance of being hit by a bus when crossing the street. However, if you perform the action of crossing the street 1000 times, then your chance …
terminology - What do you call numbers such as $100, 200, 500, …
What do you call numbers such as $100, 200, 500, 1000, 10000, 50000$ as opposed to $370, 14, 4500, 59000$ Ask Question Asked 13 years, 11 months ago Modified 9 years, 7 months ago
definition - What is the smallest binary number of $4$ bit? Is it ...
Sep 29, 2024 · In pure math, the correct answer is $ (1000)_2$. Here's why. Firstly, we have to understand that the leading zeros at any number system has no value likewise decimal. Let's …
algebra precalculus - Which is greater: $1000^ {1000}$ or $1001
The way you're getting your bounds isn't a useful way to do things. You've picked the two very smallest terms of the expression to add together; on the other end of the binomial expansion, …
Why is 1 cubic meter 1000 liters? - Mathematics Stack Exchange
Mar 7, 2015 · 0 Can anyone explain why $1\ \mathrm {m}^3$ is $1000$ liters? I just don't get it. 1 cubic meter is $1\times 1\times1$ meter. A cube. It has units $\mathrm {m}^3$. A liter is liquid …
algebra precalculus - Multiple-choice: sum of primes below $1000 ...
Jan 30, 2017 · Given that there are $168$ primes below $1000$. Then the sum of all primes below 1000 is (a) $11555$ (b) $76127$ (c) $57298$ (d) $81722$ My attempt to solve it: We …
Solving for the last two digits of a large number $3^ {1000}$?
Oct 28, 2017 · I found this question asking to find the last two digits of $3^{1000}$ in my professors old notes and review guides. What material must I know to solve problems like this …
combinatorics - Probability of winning a prize in a raffle ...
You'll be surprised. The correct probability of winning at least one ticket is around $0.2242$. Assuming exactly one prize is given, your answer of $\frac {1} {160}$ is the probability of …